409. Longest Palindrome
统计字符出现次数然后进行遍历
偶数字符直接加上,奇数字符的话,我们取出其最大偶数,
有遇到过奇数字符,就需要在结果加1,但只能加最多一次,如果结果已经是奇数就代表加过了,不需要再加。
class Solution:
def longestPalindrome(self, s: str) -> int:
length = 0
count = collections.Counter(s)
for i in count.values():
if i % 2 == 0:
length += i
else:
if (length % 2 == 0):
length += 1
length += (i-1)
return length
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